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If the vertex angle of an isosceles triangle is 50° find the other two angles. |
Answer» In an isosceles triangle, the base angles are equal, Let the each base angle be ‘x’ ∠A +∠B +∠C = 180° 50° + x + x = 180° [Sum of the angles of a traingle 180°] 50° + 2x = 180° 2x = 180° – 50° 2x = 130° x = \(\frac{130^o}{2}\) x = 65° ∴The other two angles are equal to 65° & 65° |
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