InterviewSolution
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InterviewSolution
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If the volume occupied by `CO_(2)` molecules is negligible, then calculate the pressure exerted by one mole of `CO_(2)` gas at 273 K (a=3.592 atm `"litre"^(-2)mol^(-2)`) |
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Answer» For 1 mole, `(P+(a)/(V_(2)))(V-b)=RT` If b is negligible, `(P+(a)/(V_(2)))V=RT" or " P=(RT)/(V)-(a)/(V_(2))" or "PV^(2)-RTV+a=0` This equation is quadratic in V. Hence, `V=(+RT+-sqrt(R^(2)T^(2)-4aP))/(2P)` As V can have only one value at P and T, hence we must have `R^(2)T^(2)-4aP=0 " or " R^(2)T^(2)=4 a P` or `" " P=(R^(2)T^(2))/(4a)=((0.0821" L atm "K^(-1))^(2)(273 K)^(2))/(4xx3.592" atm "L6(-2)mol^(-2))=34.96" atm"` |
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