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If the wave-front of e.m.wave travelling in vacuum is given by , `vecr=hati+hatj+hatk`, and find the angle made by the direction of propagation of e.m. wave with y-axis. |
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Answer» If `theta` is the angle which the direction of propagation of e.m. wave makes with y-axis, then `cos theta=(vecr.hatj)/r=((hati+hatj+hatk).hatj)/(sqrt((1)^2+(1)^2+(1)^2))=1/(sqrt3) or theta=cos^-1(1/(sqrt3))` |
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