1.

If the wavelength of the firsr line of the Blamer series of hydrogen atom is `6561Å` , the wavelength of the second line of the series should beA. 13122ÅB. 3280ÅC. 4860ÅD. 2187Å

Answer» Correct Answer - C
Wavlength of spectral line in Blamer series is given by
`" " (1)/(lambda)=R[(1)/(2^(2))-(1)/(n^(2))]`
For first line of Blamer series,n=3
`:." " (1)/(lambda)=R[(1)/(2^(2))-(1)/(3^(2))]=(5R)/(36)`
For second line of Balmer series n=4
`" " (1)/(lambda)=R((1)/(2^(2))-(1)/(4^(2)))=(3R)/(16)`
`:. " " (lambda_(2))/(lambda_(1))=(20)/(27)`
`:." " lambda_(1)=(20)/(27)xx6561=4860Å`


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