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If the weight of dry raisins is `W_(1)` and that of soaked raisins is `W_(2)` , then the correct equation for calculating the percentage of water absorbed by raisins will be:A. `W_(1)-W_(2)`B. `W_(2)-W_(1)`C. `(W_(2)-W_(1))/(W_(1))xx100`D. `(W_(1)-W_(2))/(W_(2))xx100` |
| Answer» Correct Answer - C | |