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If the zeroes of the polynomial f(x) = x3 – 3x2 + x + 1 are (a – b), a and (a + b), find the values of a and b. |
Answer» By using the relationship between the zeroes of he quadratic polynomial. We have, Sum of zeroes = \(\frac{-(coefficient\,of\,x^2)}{coefficient\,of\,x^3}\) ∴ a – b + a + a + b = \(\frac{-(-3)}1\) ⇒ 3a = 3 ⇒ a = 1 Now, Product of zeroes = \(\frac{-(constant\,term)}{coefficient\,of\,x^3}\) ∴ (a – b) (a) (a + b) = \(\frac{-1}1\) ⇒ (1 – b) (1) (1 + b) = –1 [∵a =1] ⇒ 1 – b2 = –1 ⇒ b2 = 2 ⇒ b = ±√2 |
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