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If the zeros of the polynomial f(x) = x3 – 3x2 + x + 1 are (a – b), a and (a + b), find a and b. |
Answer» Given: Zeros of the polynomial x3 – 3x2 + x + 1 are (a – b), a and (a + b). Now by using the relationship between the zeros of the quadratic polynomial we have: Sum of zeros = -(coefficient of x)/(coefficient of x2) = -1 a – b + a + a + b = -1 3a = 3 a = 1 Product of zeros = (constant term)/(coefficient of x2) = -1 (a – b) (a) (a + b) = -1 (1 – b) (1) (1 + b) = – 1 1 – b2 = – 1 b = ±√2 |
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