1.

If thedensity of a gas at the sea level at 0^(@)C is 1.29 kg m^(-3), what will be its molar mass ? (Assume that pressure is equal to 1 bar).

Answer»


Solution :`M=(dRT)/(P)=(1.29 kg m^(-3)xx8.314N m K^(-1) MOL^(-1)xx273 K)/(1.0xx10^(5)N m^(-2))=0.0293 kg mol^(-1)=29.3 g mol^(-1)`(1J=1 N m)


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