if thediameter of atomis 0.15nmcalculatethe number ofcarbon atom whichcan beplacedsideby sidein astraightline across lengthof scaleof length20 cm long

if thediameter of atomis 0.15nmcalculatethe number ofcarbon atom which

1.	if thediameter of atomis 0.15nmcalculatethe number ofcarbon atom whichcan beplacedsideby sidein astraightline across lengthof scaleof length20 cm long
Answer» Solution :20 CM = 20`XX 10^(7)NM`length diameterof carbonatom=0.15 nm So0.15nm space= 1carbon atom 20`xx 10^(7) nm` space = (?)carbon atom Noof carbon atoms = `(20 xx 10^(7)nm xx 1)/(0.15 nm) ` =133.3`xx10^(7)` `1.333 xx 10^(9)`CARBONATOMS