If thephotonof thewavlength150pmstrikesan atomandone of tisinnerboundelectronisejectredout witha velocityof 1.5 xx 10^(7)ms^(-7)calculatethe energywith whichit isboundtothe nucleus .

If thephotonof thewavlength150pmstrikesan atomandone of tisinnerbounde

1.	If thephotonof thewavlength150pmstrikesan atomandone of tisinnerboundelectronisejectredout witha velocityof 1.5 xx 10^(7)ms^(-7)calculatethe energywith whichit isboundtothe nucleus .
Answer» Solution :Calculationof kineticenergy massof electron(m )= 9.1 `xx10^(31) KG` velocityof ejectedelectron( v) =1.5 `xx 10^(7) NM^(1)` `KE = (1)/(92) mv^(2)` `=(1)/(2)(9.1 xx 10^(31) kg(1.5 xx 10^(7)ms^(-1) )` `=10.2375xx 10^(17)` `1.02375 xx 10^(16) kgm^(2) s^(2)` Applyingenergy `=1.3252 xx 10^(15)J =13.252xx 10^(16) J` Energybondto thenucleus `(E_(0))`= minimumenergyrequiredfor ejectredelectron(e ) `E_(0)= (E- KE)` `=(13.252 xx 10^(16) J)(1.02375xx 10^(16)J)` `=(12.228 xx 10^(16)) + (1.602 xx 10^(19))` `=7.5483 xx 10^(3) eV`