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If there are n capacitors in parallel connected to V volt source, then the energy stored is equal toA. `(1)/(2)n CV^(2)`B. `(1)/(2)(CV^(2))/(n)`C. `(1)/(2)CV^(2)`D. none of these |
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Answer» Correct Answer - B Energy stored by an system of capacitors `i` `= (1)/(2)C_("net") V^(2)` where `V` is source voltage Thus, `n` capacitors are connected in parallel, Therefore `C_("net") = nC` `:. E_("net") = (1)/(2)nCV^(2)` |
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