Saved Bookmarks
| 1. |
If `theta=(17pi)/3` then, `tantheta-cottheta`= …A. `1/(2sqrt3)`B. `(-1)/(2sqrt3)`C. `2/(sqrt3)`D. `-(2)/(sqrt3)` |
|
Answer» Correct Answer - D We have, `theta=(17pi)/3` `thereforetantheta-cottheta=tan((17pi)/3)-cot((17pi)/3))` `=tan(5pi+(2pi)/3)-cot(5pi+(2pi)/3)` `=tan(2pi)/3-cot(2pi)/3` `=tan(pi-pi/3)-cot(pi-pi/3)` `=-tanpi//3+cotpi//3` `=-sqrt3+1/sqrt3)=(-3+1)/(sqrt3)=(-2)/(sqrt3)` |
|