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If `theta=(2pi)/(2009), then costhetacos 2thetacos3theta... cos1004theta` is |
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Answer» Correct Answer - C Let `P=costhetacos2thetacos 3theta...sin1004theta` Then, `2^(1004)PQ=sin2theta sin4thetasin6theta...sin2008 theta` `implies2^(1004)PQ=(sin2thetasin4thetasin60...sin2008theta)(sin1006thetasin1008theta...sin2008theta)` `2^(1004)PQ=(sin2thetasin4thetasin6theta...sin1004theta)` `{sin(2pi-1003theta)sin(2pi-1001theta)...sin(2pi-theta)}` `implies2^(1004)PQ=(-1)^(502)sinthetasin2thetasin3thetasin4theta.....sin1003thetasin1001theta` `implies2^(1004)PQ=QimpliesP=(1)/(2^(1004))` |
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