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If TP and TQ are the two tangents to a circle with centre O so that `/_P O Q=110^@`, then `/_P T Q` is equal to |
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Answer» We know tangent at any point `P` is always perpendicular to line joining the center `O` of that circle. So, in the given figure, `/_OPT = /_OQT = 90^@` So, in rectangle `OPTQ` `/_POQ+/_PTQ+/_OPT+/_OQT = 360^@` `/_PTQ+90+90+110 = 360` `/_PTQ = 360-290 = 70^@` |
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