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If two coins are tossed simultaneously, the probability of getting two heads is :(A) \(\frac { 3 }{ 4 }\)(B) \(\frac { 1 }{ 2 }\)(C) \(\frac { 1 }{ 4 }\)(D) 1 |
Answer» Answer is (C) \(\frac { 1 }{ 4 }\) When two coins are tossed simultanously the all possible outcomes are HH, HT, TH, TT The number of all possible outcomes = 4 The number of favourable outcomes of getting two heads = 1 ∴ The probability of getting two heads = \(\frac { 1 }{ 4 }\) |
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