1.

If two dice are thrown and at least one of the dice shows 5.then the probability that the sum is 10 or more is

Answer»

`(1)/(6)`
`(4)/(11)`
`(3)/(11)`
`(2)/(11)`

Solution :A = Eventof showing5 and atleastone dice`= (1,5) , (2,5),(3,5), (4,5), (5,5),(6,5), (5,1) ,(5,2),(5,3),(5,4), (5,6)`
N (A) = 11 .
and n(s) ` = 6 XX 6 = 36`
B = Eventof Showingshows10 or morewhenat lest onedice SHOWN 5.
` = (5,5) ,(5,6),(6,5)`
n(B) = 3 .
`rArr n(A nn B) = 3`
Now, `P((B)/(A)) = (P(AnnB))/(P(A))` .
`=((n(AnnB))/(n(S)))/((n(A))/(n(S))) = ((3)/(36))/((11)/(36)) = (3)/(11)`


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