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If two dice are thrown and at least one of the dice shows 5.then the probability that the sum is 10 or more is |
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Answer» `(1)/(6)` N (A) = 11 . and n(s) ` = 6 XX 6 = 36` B = Eventof Showingshows10 or morewhenat lest onedice SHOWN 5. ` = (5,5) ,(5,6),(6,5)` n(B) = 3 . `rArr n(A nn B) = 3` Now, `P((B)/(A)) = (P(AnnB))/(P(A))` . `=((n(AnnB))/(n(S)))/((n(A))/(n(S))) = ((3)/(36))/((11)/(36)) = (3)/(11)` |
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