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If two particles performing SHM, are given by, `x_(1)=10 sin[3pi t +(pi//4)] and ` `x_(2)=5[sin 3pi t +sqrt(3) cos 3 pi t]` then the ratio of their amplitudes isA. `2 : 1`B. `1 : 1`C. `1 : 2`D. `1 : sqrt(2)` |
Answer» Correct Answer - B `y_(2)=5sin3pit+5sqrt(3)cos3pit` `R_(1)=sqrt(A_(1)^(2)+A_(2)^(2)+2A_(1)A_(2)cosalpha_(1)-alpha_(2))` `=sqrt(25+25xx3+25xxsqrt(3)xxcos(pi//2))` `=sqrt(25+75)=sqrt(100)` `R_(1)=10cmR_(2)=10cm` `(R_(1))/(R_(2))=(10)/(10)=(1)/(1)` |
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