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If two sets `A & B` are having `99` elements in common, then the number of elements common to the sets `AxxB` and `BxxA` areA. `2^(99)`B. `99^(2)`C. `100`D. `18` |
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Answer» Correct Answer - B If two sets `A & B` ………………. Let `A{a_(1), a_(2), a_(3), … a_(99), b_(1), b_(2),….}` Let `B{a_(1), a_(2), a_(3), …a_(99), c_(1), c_(2)…}` `AxxB = {(a_(1), a_(1)), (a_(1), a_(2))…(a_(1)a_(99)), (a_(1),c_(1)),…… (a_(2),a_(1))…}` `BxxA={(a_(1),a_(1)),(a_(1),a_(2))...(a_(1)a_(99),(a_(1)b_(1))...(a_(2),a_(1))...}` Clearly common `(a_(1), a_(2)),.......(a_(1)a_(99)), (a_(2),a_(1)), ....(a_(2),a_(99))`, ......... `:. 99xx99=99^(2)` |
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