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If two waves of same frequency and same amplitude superimpose and produce third wave of same amplitude, then waves differ in phase by –A. zeroB. `pi`C. `pi//2`D. `pi//4` |
Answer» Correct Answer - D `A_(R)=sqrt(A_(1)^(2) + A_(2)^(2) + 2A_(1)A_(2) cos theta)` where `theta ` is the phase difference between the waves but `A_(R) = A_(1) = A_(2) = A` So, `" "A^(2) = A^(2) + 2A^(2) cos theta` `" "cos theta = -(1)/(2)` `" " theta = -(2pi)/(3)` |
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