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If u=a-b and v=a+b and |a|=|b|=2, then |uxx v| is equal to |
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Answer» `2sqrt(16-(a.b)^(2))` `[because axxa =bxxb=0]` and `|axxb|^(2)+(a*b)^(2)=(ab SIN theta)^(2)+(ab cos theta)^(2)=a^(2)b^(2)` `|axxb|=sqrt(a^(2)b^(2)-(a*b)^(2))` So`|uxxv|=2|axxb|=2sqrt(a^(2)b^(2)-(a*b)^(2))` `=2sqrt(2^(2)2^(2)-(a*b)^(2))` `=2sqrt(16-(a*b)^(2))[because |a|=|b|=2]` |
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