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If u = log(tan x + tan y + tan z) then du/dy is |
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Answer» u = log (tan x + tan y + tan z) \(\cfrac{du}{dy}\) = \(\cfrac{1}{tan x + tan y + tan z}\). \(\cfrac{d}{dy}\) tan y \(\cfrac{du}{dy}\) = \(\cfrac{sec^2y}{tanx+tany+tanz}\) |
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