1.

If u = log(tan x + tan y + tan z) then du/dy is

Answer»

u = log (tan x + tan y + tan z)

\(\cfrac{du}{dy}\) = \(\cfrac{1}{tan x + tan y + tan z}\)\(\cfrac{d}{dy}\) tan y

\(\cfrac{du}{dy}\) = \(\cfrac{sec^2y}{tanx+tany+tanz}\)



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