If uncertainties in the measurement of position and momentum of an electron are found to be equal in magnitude, what is the uncertainty in the measurement of velocity of the electron ? Comment on the result obtained

If uncertainties in the measurement of position and momentum of an ele

1.	If uncertainties in the measurement of position and momentum of an electron are found to be equal in magnitude, what is the uncertainty in the measurement of velocity of the electron ? Comment on the result obtained
Answer» Solution :`Deltax xx Delta p = (h)/(4pi)`. As `Delta X = Deltap :. (Deltap)^(2) = (h)/(4pi) or Deltap = sqrt((h)/(4pi)) or m xx Deltav = sqrt((h)/(4pi))` or `Delta v = (1)/(m) sqrt((h)/(4pi)) =(1)/(9.11 xx 10^(-31)) xx sqrt((6.626 xx 10^(-34))/(4 xx 3.14)) = (0.726 xx 10^(-17))/(9.11 xx 10^(-31)) = 7.98 xx 10^(12) ms^(-1)` THUS, uncertainty in velocity is GREATER than the velocity of light which is impossible. Thus, the two uncertainties cannot be EQUAL in magnitude.