InterviewSolution
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InterviewSolution
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If units of length, mass and force are chosen as fundamental units, the dimensions of time would be :A. `M^(1//2) L^(-1//2) F^(1//2)`B. `M^(1//2) L^(1//2) F^(1//2)`C. `M^(1//2) L^(1//2) F^(-1//2)`D. `M^1 L^(-1//2) F^(-1//2)` |
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Answer» Correct Answer - (c ) `F = M^1 L^1 T^(-2)` `:. T^2 = (M^1 L^1)/(F) or T = M^(1//2) L^(1//2) F^(-1//2)` |
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