If v=(10+-0.2)volt and I=(5+-0.1) amper

1.	If v=(10+-0.2)volt and I=(5+-0.1) amper
Answer» Answer: 2+-0.04 Explanation: it is GIVEN using the law of error analysis. we know that r=V/i. therefore now, using error analysis to get the max. possible error in r. (delta r)/r=(delta v)/v+(delta i)/i by error analysis FORMULA . so we get , (delta r)/r= 0.2/10+0.1/5(see here the sign of the error is always POSITIVE i.e, all the errors will be ADDED in the same way of they are in division). (delta r)/r=0.04. And by r=v/i. we get r=10/5=2ohm. Therefore the ans is: r=2+-0.04

Answer»

Answer:

2+-0.04

Explanation:

it is GIVEN using the law of error analysis.

we know that r=V/i.

therefore now, using error analysis to get the max. possible error in r.

(delta r)/r=(delta v)/v+(delta i)/i

by error analysis FORMULA .

so we get ,

(delta r)/r= 0.2/10+0.1/5(see here the sign of the error is always POSITIVE i.e, all the errors will be ADDED in the same way of they are in division).

(delta r)/r=0.04.

And by r=v/i.

we get r=10/5=2ohm.

Therefore the ans is: r=2+-0.04

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If v=(10+-0.2)volt and I=(5+-0.1) amper

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