If v= (3i + 4j+ 5k) ms^(-1) is the instantaneous velocity of a body of mass 1.50kg. Calculate its kinetic energy.

If v= (3i + 4j+ 5k) ms^(-1) is the instantaneous velocity of a body of

1.	If v= (3i + 4j+ 5k) ms^(-1) is the instantaneous velocity of a body of mass 1.50kg. Calculate its kinetic energy.
Answer» SOLUTION :`V= (3I + 4j + 5k) MS^(-1) M= 1.5kg` Kinetic ENERGY K.E `= (1)/(2) MV^(2)` `=(1)/(2) 1.5 (3i + 4j + 5k) .(3i + 4j+ 5k)= 37.5` joules