If v=(3i+4j+5k)ms^(-1) is the instantaneous velocity of a body of mass 1.50 kg. calculate its kinetic energy.

If v=(3i+4j+5k)ms^(-1) is the instantaneous velocity of a body of mass

1.	If v=(3i+4j+5k)ms^(-1) is the instantaneous velocity of a body of mass 1.50 kg. calculate its kinetic energy.
Answer» Solution :`V=(3i+4j+5k)MS^(-1)M=1.5 KG` KINETIC energy K.E. `=(1)/(2)mv^(2)` `=(1)/(2)1.5(3i+4j+5k).(3i+4j+5k,)` = 37.5 joules.