1.

If `v` is the volume of one molecule of a gas under given conditions, then van der Waals constant `b` isA. `4v`B. `4v//N_(0)`C. `N_(0)//4v`D. `4vN_(0)`

Answer» `b` is equal to `4 times` the volume of molecules in one
mole of a gas (`N_(0)` molecules)
Volumes of one molecule `=v`
Volume of `N_(0)` molecule `=vN_(0)`
Hence, `b=4vN_(0)`


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