If `V = sqrt(gammap)/(rho)`, then the dimensions of `gamma` will be (where p is pressure, `rho` is density and V is velocity) :A. `M^(0)L^(0)T^(0)`B. `M^(0)L^(0)T^(1)`C. `M^(1) L^(0) T^(0)`D. `M^(0) L^(1) T^(0)`

If `V = sqrt(gammap)/(rho)`, then the dimensions of `gamma` will be (w

1.	If `V = sqrt(gammap)/(rho)`, then the dimensions of `gamma` will be (where p is pressure, `rho` is density and V is velocity) :A. `M^(0)L^(0)T^(0)`B. `M^(0)L^(0)T^(1)`C. `M^(1) L^(0) T^(0)`D. `M^(0) L^(1) T^(0)`
Answer» Correct Answer - A `gamma = v^(2) (rho)/(p)` `[gamma] = M^(0)L^(0)T^(0)`

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If `V = sqrt(gammap)/(rho)`, then the dimensions of `gamma` will be (where p is pressure, `rho` is density and V is velocity) :A. `M^(0)L^(0)T^(0)`B. `M^(0)L^(0)T^(1)`C. `M^(1) L^(0) T^(0)`D. `M^(0) L^(1) T^(0)`

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