If v = \(\sqrt{s^2 + 1}\) prove that acceleration is ‘S’ (V = vel – InterviewSolution

1.

If v = \(\sqrt{s^2 + 1}\) prove that acceleration is ‘S’ (V = velocity, S = displacement).

Answer»

Given v = \(\sqrt{s^2 + 1}\)

Acceleration = \(\frac{ds}{dt}\)

= \(\frac{1}{2\sqrt{s^2 + 1}}.2s\frac{ds}{dt}\) = \(\frac{1}{2v}\).2.s.v.s units/sec².

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