If variance of normal distribution is √9 cms, then find the quartile

1.	If variance of normal distribution is √9 cms, then find the quartile deviation.
Answer» Variance = σ² = 9 ∴σ² = √9 = 3. In a normal distribution quartile deviation = \(\frac{2}{3}σ = \frac{2}{3} \times 3 = 2\).

If variance of normal distribution is √9 cms, then find the quartile deviation.

Answer»

Variance = σ² = 9

∴σ² = √9 = 3.

In a normal distribution quartile deviation

= \(\frac{2}{3}σ = \frac{2}{3} \times 3 = 2\).