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If \(|\vec P + \vec Q|\) = \(|\vec P|\) - \(|\vec P|\), then the angle between the vectors \(\vec P\) and \(\vec Q\)(a) 0° (b) 90°(c) 180° (d) 360° |
Answer» (c) 180° \(|\vec P + \vec Q|\) = \(|\vec P|\) \(|\vec P|\) Square on both side, and the resultant becomes P2 + Q2 + 2PQ cos θ = P2 + Q2 – 2PQ . cos θ = -1 θ = 180° |
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