1.

If veca = (2,-2,1), vecb = (2,3,6) and vecc = (-1,0,2), Find the magnitude and direction of veca-vecb+2vecc.

Answer»

Solution :`veca-vecb+2vecc = (2,-2,1) - (2,3,6) + 2(-1,0,2)
= (2,-2,1) + (-2,-3,-6) + (-2,0,4)
= (2-2,-2,-2-3+0, 1-6+4)
= (-2, -5, -1)
MAGNITUDE of `veca-vecb+2vecc = sqrt(4+25+1) = sqrt(30)`
D. CS of `veca-vecb+2vecc` are `-2/sqrt(30), -5/sqrt(30), -1/sqrt(30)`


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