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If `vecA=2hati+hatj-hatk. vecB=hati+2hatj+3hatk and vecC=6hati-2hatj-6hatk` then the angle between `(vecA+vecB) and vecC` will be :-A. `30^(@)`B. `45^(@)`C. `60^(@)`D. `90^(@)` |
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Answer» Correct Answer - D `vecA+vecB=vecD` `vecD=3hati+3hatj+2hatk" , "vecC=6hati-2hatj-6hatk` `vecDvecC=18-6-12=0` `theta=90^(@)` |
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