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If veca = 3hati+hatj-2hatk, vecb = 2hati-3hatj+4hatk then verify that vecaxxvecb is perpendicular to both veca and vecb. |
Answer» Solution : Now `(vecaxxvecb).VECA` = `(10hati-8hatj-11hatk).)3hati+hatj+2hatk)` =30-8-22 = 0 Again `(vecaxxvecb).VECB` = `(10hati-8hatj-11hatk).(2hati-3hatj+4hatk)` = 20+24-44 = 0 HENCE `vecaxxvecb` is PERPENDICULAR to both `veca` and `vecb`.(PROVED). |
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