1.

If vecalpha =x(vecx xx vecb) + y(vecb xx vecc) + z(vecc xx veca) and [veca.vecb.vecc]=1/8, then x+y+zis equal to:

Answer»

`8vecalpha.(veca+VECB +VECC)`
`VECALPHA.(veca + vecb + vecc)`
`8(veca + vecb+ vecc)`
None of these

Answer :A


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