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If vector a = 4i + 3j + 2k and vector b = 3i + 2k then find vector|b x 2a| |
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Answer» We have vector a = 4i + 3j + 2k 2 vector a = 8i + 6j + 4k and vector b = 3i + 2k = 3i + 0j + 2k ∴ vector|b x 2a| = |(i,j,k),(3,0,2),(8,6,4)| = i(0 - 12) - j(12 - 16) + k(18 - 0) = -12i + 4j + 18k ∴ vector|b x 2a| = √(122 + 42 + 182) = √484 = 2√121 = 22 |
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