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If vector `(hata+ 2hatb)` is perpendicular to vector `(5hata-4hatb)`, then find the angle between `hata and hatb`. |
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Answer» Correct Answer - `60^(@)` `because (hata+ 2hatb) `is perpendicular to`(5hata-4hatb)` `therefore (hata+ 2hatb) *( 5hata - 4hatb) =0` `rArr 5hata*hata- 4hata*hatb+ 10 hatb*hata- 8hatb*hatb=0` `rArr 5+ 6hata*hatb-8=0` `rArr 6hata* hatb=3` `rArr hata*hatb= (1)/(2)` `rArr cos theta = (1)/(2)` `rArr theta = 60^(@)` |
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