If vector vecA =4 hati -6 hatJ +2hatk and vecB =6hati +8 hatj +mhatk are m utually perpendicular, m = ....

If vector vecA =4 hati -6 hatJ +2hatk and vecB =6hati +8 hatj +mhatk a

1.	If vector vecA =4 hati -6 hatJ +2hatk and vecB =6hati +8 hatj +mhatk are m utually perpendicular, m = ....
Answer» 24 12 20 36 Solution :`vec(A ) _\|_ vec(B ) ` so `vec( A ) . Vec(B ) = 0` `(4hat(I )- 6hat(j )+ 2hat(K )) (hat(I )= 8hat(I )+ MHAT(k )) = 0` `2 m=24` `m=12 `