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If velocity (in ms^(-1)) varies with time as V = 5t, find the distance travelled by the particle in time interval of t = 2s to t = 4 s. |
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Answer» 24 m `therefore (dx)/( dt) = 5t (because V = (dx)/(dt))` `therefore dx= 5t dt` TAKING integration `int _(20) ^(x) DZ = 5 int _(2) ^(4) t dt` `(because t = 2s ` to `t = 4s)` `therefore x =5 [ (t ^(2))/( 2) ] _(2) ^(4) = 5 [8-2]` `therefore x = 30,` |
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