1.

If velocity (in ms^(-1)) varies with time as V = 5t, find the distance travelled by the particle in time interval of t = 2s to t = 4 s.

Answer»

24 m
30 m
10 m
20 m

Solution :Here, V = 5t is given.
`therefore (dx)/( dt) = 5t (because V = (dx)/(dt))`
`therefore dx= 5t dt`
TAKING integration `int _(20) ^(x) DZ = 5 int _(2) ^(4) t dt`
`(because t = 2s ` to `t = 4s)`
`therefore x =5 [ (t ^(2))/( 2) ] _(2) ^(4) = 5 [8-2]`
`therefore x = 30,`


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