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If velocity of light, acceleration due to gravity and normal atmospheric pressure are taken as the fundamental units, what will be the units of mass, length and time, given velocity of light as 3xx10^(8) ms^(-1) acceleration due to gravity 10ms^(-2) and normal pressure =10^(5)Nm^(-2) |
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Answer» <P> Dividing the 1st two equation `T=3xx10^(8)//10=3xx10^(7)s`. Multiplying first and fourth `LT^(-1)xxT=L=3xx10^(8)xx3xx10^(7)=9xx10^(15)m`. Substituting in the 3rd EQUATIO `M=10^(5)//L^(-1)T^(2)=10^(5)xx9xx10^(15)xx9xx10^(14)=81xx10^(34)kg`. |
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