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If voltage across a bulb rated 22 volt 100 watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease isA. 0.05B. 0.1C. 0.2D. 0.025 |
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Answer» Correct Answer - 0.01 `PpropV^(2)` So `(DeltaP)/(P)=2(DeltaV)/(V)=5%` |
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