InterviewSolution
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InterviewSolution
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If volume occupied by `CO_(2)` molecules is negligible, then calculate pressure `((P)/(5.277))` exerted by one mole of `CO_(2)` gas at `300 K`. `(a=3.592 atm L^(2)mol^(-2))`A. 7B. 8C. 9D. 3 |
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Answer» Correct Answer - B `(P+(an^(2))/(V^(2)))(V-nb)=nRT` `(P+(a)/(V^(2)))(V-b)=RT " " (because n = 1)` If b is negligible `P=(RT)/(V)-(a)/(V^(2))` The equation is quadratic in V, thus `V= (+ RT pm sqrt(R^(2)T^(2)-4aP))/(2P)` Since V has one value at given P and T, thus numerical value of discriminant = 0 `R^(2)T^(2)=4aP` `P=(R^(2)T^(2))/(4a)=((0.0821)^(2)(300)^(2))/(4xx3.592) therefore (P)/(5.277)=8` |
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