1.

If volume of the gas is very large, then the second virial coefficient B in virial equation is

Answer»

`(b+(a)/(RT))`
`(b-(a)/(RT))`
`(b+(a)/(RTV))`
`(b-(a)/(RTV))`

Solution :`(P+(a)/(V^(2)))(V-b)=RT`
`PV+(a)/(V)-(ab)/(V^(2))-Pb=RT`
If V is very large, `(ab)/(V^(2))` can be neglected. HENCE,
`PV+(a)/(V)-Pb=RT`
or `PV=RT+Pb=(a)/(V)=RT+(RT)/(V)b-(a)/(V)`
`=RT[1+(1)/(V)(b-(a)/(RT))]`
COMPARING with the virial EQUATION
`PV=RT[1+(1)/(B)+...]`
`B=b-(a)/(RT)`


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