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If w is a root of the equation x2+x+1=0. The expression An=n∑r=1(r−w)(r−w2) and Bn=n∑r=1(r+w)(r+w2), then the value of sin[(An−Bn)⋅πn] is |
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Answer» If w is a root of the equation x2+x+1=0. The expression An=n∑r=1(r−w)(r−w2) and Bn=n∑r=1(r+w)(r+w2), then the value of sin[(An−Bn)⋅πn] is |
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