If we take 2.2 g of CO_2, 6.02 xx 10^21 atoms of nitrogen and 0.03 gram atom of oxygen, then the molar ratio of C,N and O atom will be

If we take 2.2 g of CO_2, 6.02 xx 10^21 atoms of nitrogen and 0.03 gra

1.	If we take 2.2 g of CO_2, 6.02 xx 10^21 atoms of nitrogen and 0.03 gram atom of oxygen, then the molar ratio of C,N and O atom will be
Answer» `1:2:5` `5:1:3` `5:1:2` `2:5:3` Solution :MOLES of `CO_2 =(2.2)/(44) =0.05` Moles of N `= (6.02xx10^(21))/(6.02xx10^(23))=0.01` Moles of O = 0.03 MOLAR ratio `CO_2 :N: O` is 0.05 : 0.01 : 0.03 is 5 : 1 : 3