If we take 44 g of CO_(2) and 14 g of N_(2). What will be the mole fraction of CO_(2) in the mixture?

If we take 44 g of CO_(2) and 14 g of N_(2). What will be the mole fra

1.	If we take 44 g of CO_(2) and 14 g of N_(2). What will be the mole fraction of CO_(2) in the mixture?
Answer» `1/5` `1/3` `2/3` `1/4` SOLUTION :Number of moles of `CO_(2)=(44)/(44)=1` Number of moles of `N_(2)=(14)/28)=0.5` `therefore` Mole of fraction of `CO_(2)=(1)/(1+0.5)=(1)/(1.5)or= (2)/(3)`