1.

If `x=-(1)/(2)` is a solution of the quadratic equation `3x^(2)+2kx-3=0`, find the velue of k.

Answer» Correct Answer - `k=(-9)/(4)`
Since `x=(-1)/(2)` is a solution of `3x^(2)+2kx-3=0,` we have
`3xx((-1)/(2))^(2)+2kxx((-1)/(2))-3=0`
`implies" "(3)/(4)-k-3=0impliesk=((3)/(4)-3)=(-9)/(4).`


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