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If `x=1/(2+sqrt3)`,find the value of `x^(3)-x^(2)-11x+4` |
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Answer» as `x=1/(2+sqrt3xx(2-sqrt3)/(2-sqrt3)=(2-sqrt3)/((2)^(2)-(sqrt3)^(2))` `x=(2-sqrt3)/(4-3)=2-sqrt3` `x-2=-sqrt3` squaring both sides , we get `(x-2)^(2)=(-sqrt3)^(2)rArrx^(2)+4-4x=3` `rArr x^(2)-4x+1=0` Now `x^(3)-x^(2)-11x+41` `=x^(3)=4x^(2)+x+3x^(2)-12x+4` `=x(x^(2)-4x+1)+3(x^(2)-4x+1)+1=xxx0+3(0)+1=0+0=0=1` |
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