

InterviewSolution
Saved Bookmarks
1. |
If `x=1//3,`find the greatest tem in the expansion of `(1+4x)^8dot` |
Answer» Correct Answer - `T_(6) = 56(4/3)^(5)` We have Now, `(T_(r+1))/(T_(r)) = (n-r+1)/(r ) (4x) = (9-r)/(r ).(4)/(3)` (Putting `n = 8, x=1//3`) `:. (T_(r+1))/(T_(r)) ge 1` `rArr 36-4r ge 3r` `rArr 36 ge 7r` `rArr r le 51/7` Hence `r = 5`, and therefore, `T_(5+1)` i.e., `6^(th)` term is greatest. `rArr T_(6) = .^(8)C_(5)(4x)^(5) = (8!)/(5! xx 3!) .(4/3)^(5)` `= (8xx7xx6)/(6) (4/3)^(5)` `= 56(4/3)^(5)` |
|