if x-1 is factor of 2x^2+kx+root2 then find the value of k.

1.	if x-1 is factor of 2x^2+kx+root2 then find the value of k.
Answer» X-1=0X=1P(x)=2x^2+kx+root2Now puting x value as 1P(x)=2(1)^2+k(1)+root2=0(Because x-1 is the factor of p(x))P(x)=2^2+k+root2=04+k+root2=0(Transposing 4 and root2 on RHS side)K=-4-root2K=-(4+root2)Thus value of k is -(4+root2)

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